CUET PG MCA Time and Work Previous Year Question Paper and Solution with PDF

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If 2 cats catch 2 mice in 2 minutes, how many cats are needed to catch 18 mice in 18 minutes?

By the formula

$\frac{M_1 H_1 D_1}{W_1}$ =

$\frac{M_2 H_2 D_2}{W_2}$ ----(i)

Here

$M_1=2, H_1=2, W_1=2$

$M_2=?, H_2=18, W_2=18$

Using (i)

$\frac{2 \times 2 \times 1}{2}$ =

$\frac{M_2 \times 18 }{18}$

$M_2=2$

Hence, 2 cats are needed to catch 18 mice.

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